Types of physics movie#

How fast was the truck moving at the moment of impact? StrategyДЄt first it may seem we donвЂ™t have enough information to solve this problem. The measured coefficient of friction between the carвЂ™s tires and the road was 0.62. The truck comes to an instantaneous stop the car slides straight ahead, coming to a stop after sliding 10 meters. Conservation of momentum here reads:ДЄt a stoplight, a large truck (3000 kg) collides with a motionless small car (1200 kg). Velocity of the hammer before hitting Iron ManД¬ombined velocity of Iron Man + hammer after the collisionДЄgain, Iron ManвЂ™s initial velocity was zero. The choice here is the system (hammer + Iron Man), from the time of collision to the moment just before Iron Man and the hammer hit the tree.

First, we posit conservation of momentum.

Because this is a one-dimensional problem, we can go directly to the scalar form of the equations. We use the given numbers to estimate the initial momentum, the initial kinetic energy, and the final kinetic energy. Thus, with the correct choice of a closed system, we expect momentum is conserved, but not kinetic energy.

Estimate how much kinetic energy was lost in this collisionДЄfter the collision, ThorвЂ™s hammer is in contact with Iron Man for the entire time, so this is a perfectly inelastic collision.

Assuming Iron ManвЂ™s total mass is 200 kg: Also from the video, Iron ManвЂ™s trajectory to the tree is very close to horizontal. The tree is about 2 m behind Iron Man, which he hits in about 0.75 s. The distance between Thor and Iron Man is approximately 10 m, and the hammer takes about 1 s to reach Iron Man after Thor releases it. From the video, Iron Man is standing still when the hammer hits him. At the beginning of the fight, Thor throws his hammer at Iron Man, hitting him and throwing him slightly up into the air and against a small tree, which breaks.

Types of physics movie#

The 2012 movie вЂњThe AvengersвЂќ has a scene where Iron Man and Thor fight. For a bow and arrow, it is elastic potential energy in the bowstring. In the case of gunpowder burning and pushing out a bullet, chemical potential energy is converted to kinetic energy of the bullet, and of the recoiling gun. Where does the energy come from? Does conservation of energy still hold? Yes some form of potential energy is converted to kinetic energy. This interaction-one object becoming many, with an increase of kinetic energy of the system-is called an explosion. Thus, we see that, although the momentum of the system is conserved in an explosion, the kinetic energy of the system most definitely is not it increases.

However, the system will have a great deal of kinetic energy after the explosion, although it had none before. After the explosion, the net momentum of all the pieces of the object must sum to zero (since the momentum of this closed system cannot change). Note that if the object is initially motionless, then the system (which is just the object) has no momentum and no kinetic energy. These can be difficult to analyze if the number of fragments after the collision is more than about three or four but nevertheless, the total momentum of the system before and after the explosion is identical. An example of this is a firecracker, or a bow and arrow, or a rocket rising through the air toward space.

The first possibility is that a single object may break apart into two or more pieces.